8.
An object is thrown vertically upward to a height of 10 m.Calculate its velocity with which it was
thrown upwards and time taken by it to reach a height of 10 m.
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3
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Answered by
2
Explanation:
v = 0 at maximum height
h = 10m
v = ?
Using equations of motion
v^2 - u^2 = 2aS
0 - u^2 = 2x-10x10
u^2 = 200
u = 14.1 m/s
now use
v = u + at
0 = 14.1 + -10xt
t = 14.1/10
t = 1.43 s
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