8.
angelABC is issosceles with AB = AC= 7.5cm
and BC = 9 cm (Fig 11.26) The Height Ad
from A to BC is 6 CM. Find the
area of angle ABC what will be the
height from C to AB ie., CE?
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Answer:
In ΔABC, AD=6cm and BC=9cm
Area of triangle=
2
1
×base×height=
2
1
×BC×AD
=
2
1
×9×6=27 cm
2
Again, Area of triangle=
2
1
×base×height=
2
1
×AB×CE
⇒27=
2
1
×7.5×CE
⇒ CE=
7.5
27×2
⇒ CE=7.2cm
Thus, height from C to AB i.e., CE is 7.2cm.
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