Question

8 अपॉन एक्स प्लस 3 माइनस 3 अपॉन टू माइनस एक्स इक्वल टू 2 quadratic equation​

Answer 1

Step-by-step explanation:

$\frac{8}{x + 3} - \frac{3}{2 - x} = 2 \\ \frac{16 - 8x - 3x - 9}{(x + 3)(2 - x)} = 2 \\ \frac{16 - 11x - 9}{x(2 - x) + 3(2 - x)} = 2 \\ \frac{16 - 11x - 9}{2x - {x}^{2} + 6 - 3x } = 2 \\ \frac{16 - 11x - 9}{ - {x}^{2} - x + 6 } = 2 \\ 16 - 11x - 9 = - 2 {x}^{2} - 2x + 12 \\ - 2 {x}^{2} - 2x + 12 - 16 + 11x + 9 = 0 \\ - 2 {x}^{2} + 9x + 5 = 0 \\ 2 {x}^{2} - 9x - 5 = 0 \: ans \\ 2 {x}^{2} - 10x + x - 5 = 0 \\ 2x(x - 5) + 1(x - 5) = 0 \\ (x - 5)(2x + 1) = 0 \\ x - 5 = 0 \: \: and \: \: 2x + 1 = 0 \\ x = 5 \: and \: 2x = - 1 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: x = - \frac{1}{2} ans$