Question

| 8. At a given temperature the pressure of a gas reduces to 75% of its initial value and the volume
increases by 40% of its initial value. Find this temperature if the initial temperature was -10°C.
[3.15°C]
123. please solve this​

Answer 1

Answer:

T1 = -10 + 273 K = 263 K

Initial pressure = P1

Initial volume = V1

T2 = ??????

P2 = 75% of P1 = 3P1/4

V2 = V1 + 40% of V1 = 7V1/5

By Ideal Gas Law,

P1V1/T1 = P2V2/T2

or, P1V1/263 = (3/4)×(7/5)× P1V1/T2

or, T2 = 21×263÷20 K (After cancelling P1 and V1)

or, T2 = 276.15 K = 276.15 - 273 °C

or, T2 = 3.15°C

I hope you understand the explanation.

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