Question

8. Calculate the area of the designed region in figure, common
between the two quadrants of the circles of radius 10 cm each.
(use n = 3.14)​

Answer 1

Step-by-step explanation:

Area of DBC=

2πr2=25π

area of ABD= 2πr2 =25π

∴ area of designed region =50π−100

=50×3.14−100

= 314/2−100 =157−100 =57 cm2

Answer 2

Answer:

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Step-by-step explanation:

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