Question

8. CH3Br + AgCN ---->?

a) Methyl cyanide
b) Methyl carbylamine
c) Methane nitrile
d) Ethane nitrile​

Answer 1

Answer:

CH3Br + AgCN ---->?

Explanation:

b) methyl carbylamine

Answer 2

After completing the following equation, it becomes-

CH3Br + AgCN ----> CH3CN + AgBr

Methyl Bromide + Silver Cyanide ---->  Methyl Cyanide + Silver Bromide

• If we mix Methyl Bromide (CH₃Br) and Alcoholic Silver Cyanide (AgCN), the main product that comes out is Isocyanide ( CH₃NC).
• The reason behind this is the attack that occurs due to N atom. It results in isocyanide ion, NC⁻.