Question

8 chairs and table of classroom cost is Rs 10,500 while 5 chairs and 3 tables cost is Rs 6, 450 find cost of each chair and that of each table ​

Answer 1

Answer:

750,900

Step-by-step explanation:

Let the cost of a chair is x Rs and the cost of a table is y Rs.

Then,

8x+5y=10500→(1)

5x+3y=6450→(2)

Multiplying (1) with 3 and (2) with 5, and then subtracting (2) from (1),

24x+15y−25x−15y=31500−32250

−x=−750⇒x=750

Putting value of x in (1),

8(750)+5y=10500

⇒5y=10500−6000

⇒y=900

∴ Cost of the chair is 750 Rs and cost of the table is 900 Rs.

Answer 2

✬ Each Chair cost = Rs 750 ✬

✬ Each Table cost = Rs 900 ✬

Step-by-step explanation:

Given:

• Cost of 8 chairs and 5 tables of a classroom is Rs 10500.
• Cost of 5 chairs and 3 tables is Rs 6450

To Find:

• Find the cost of each chair and that of each table.

Solution: Let the cost of each table be Rs y and that of each chair be Rs x.

• 8 chair's cost = 8x
• 5 table's cost = 5y

∴ Cost of both items = 8x + 5y = Rs 10,500......(1)

• 5 chair's cost = 5x
• 3 table's cost = 3y

∴ Cost of both items = 5x + 3y = Rs 6450 .......(2)

• Multiply the equation 2 by 5 •

$\small\implies{\sf }$ 5 (5x + 3y) = 5 (6450)

$\small\implies{\sf }$ 25x + 15y = 32250

• Also multiply the equation 1 by 3 •

$\small\implies{\sf }$ 3 (8x + 5y) = 3 (10500)

$\small\implies{\sf }$ 24x + 15y = 31500

★ Subtracting the obtained results we get ★

25x + 15y = 32250

24x + 15y = 31500

– – = –

_______________

x = 750

★ Putting the value of x in equation 1 , we get ★

$\small\implies{\sf }$ 8x + 5y = 10500

$\small\implies{\sf }$ 8(750) + 5y = 10500

$\small\implies{\sf }$ 6000 + 5y = 10500

$\small\implies{\sf }$ 5y = 10500 – 6000

$\small\implies{\sf }$ y = 4500/5

$\small\implies{\sf }$ y = 900

Hence, The cost of each chair is x = Rs 750 and cost of each table is y = Rs 900.