8. Choose the correct option for the quantum numbers of the last electron of K+.
(A) 4, 0, 0, +1/2
(B) 3, 1,-1, -1/2
(C) 4, 1, 0,
(C)4, 1, 0, -
(D) 3,0, 1,
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Answer:
E.C of Rubidium is (Z=37) = 1s
2
2s
2
2p
6
3s
2
3p
6
4s
2
3d
10
4p
6
5s
1
The valence electron is in 5s orbital.
Its 4 quantum numbers are- n=5,l=0,m=0,s=+
2
1
Therefore, the correct option is C
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