Question

8 cm
16. Calculate the area of the designed region in
Fig. 12.34 common between the two quadrants
8 cm​

Answer 1

Step-by-step explanation:

Area of designed region = Area of 1st quadrant + Area of 2nd quadrant Area of square Area of 1st quadrant = /360 2 = 90/360 22/7 82 = 1/4 22/7 8 8 = 22/7 2 8 = 352/7 cm2 For 2nd quadrant, As radius and angle are same Area of 2nd quadrant = Area of 1st quadrant = 352/7 cm2 Now , Area of square = side side = 8 8 = 64 cm2 Area of designed region = Area of 1st quadrant + Area of 2nd quadrant Area of square = (352/7+352/7 64) = ((352 +352 64 7)/7) = ((704 448)/7) = 256/7 cm2

Answer 2

Step-by-step explanation:

Area= theta/360*πr²

= 90/360*22/7*8*8

=1/4*3.14*8*8

=3.14*16

=50.24...ans