8 cm 5 cm tall A painting is drawn on a wide cardboard in such a way that 1.5 cm along each of its sides is drawn. The margin has been omitted. What will be the total area of the margin?
(A) 40 sq. cm
(B) 30 sq. cm.
(C) 22.5 sq. cm.
(D)9 sq.cm
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2
Correct answer:-
option (B).
Explanation:-
Length of painted cardboard=8 cm and breadth of painted card =5cm
Since, there is a margin of 1.5cm long from each of its side.
Therefore reduced length
=8−(1.5+1.5)=8−3=5cm
And reduced breadth
=5−(1.5+1.5)=5−3=2cm
∴ Area of margin=Area of cardboard(ABCD)−Area of cardboard(EFGH)
=(AB×AD)−(EF×EH)
=(8×5)−(5×2)
=40−10
=30cm^2
Thus, the total area of margin is 30cm^2.
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Answered by
3
Answer:
Length of painted cardboard=8 cm and breadth of painted card =5cm
Since, there is a margin of 1.5cm long from each of its side.
Therefore reduced length
=8−(1.5+1.5)=8−3=5cm
And reduced breadth
=5−(1.5+1.5)=5−3=2cm
∴ Area of margin=Area of cardboard(ABCD)−Area of cardboard(EFGH)
=(AB×AD)−(EF×EH)
=(8×5)−(5×2)
=40−10
=30cm
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