Question

8 coins are tossed simultaneously . find the probability of getting 1)at least 6 heads 2)no heads​

Answer 1

Step-by-step explanation:

The required probability =

8

C

6

(

2

1

)

6

.(

2

1

)

2

+

8

C

7

(

2

1

)

7

(

2

1

)+

8

C

8

(

2

1

)

8

. =

256

1

(28+8+1)=

256

37

.

Please mark me as a brainliest answer

Answer 2

Step-by-step explanation:

your answer is in attachment...