Question

8. CONDITIONAL PROBABILITIES Often it is required to compute the probability of an event given that another event has occurred. For example, what is the probability that two cards drawn at random from a deck of playing cards will both be aces? It might seem that you could use the formula for the probability of two independent events and simply multiply 4/52 x 4/52 = 1/169. This would be incorrect, however, because the two events are not independent. If the first card drawn is an ace, then the probability that the second card is also an ace would be lower because there would only be three aces left in the deck. Once the first card chosen is an ace, the probability that the second card chosen is also an ace is called the conditional probability of drawing an ace.

i) Find the probability of drawing 2 Aces from the deck simultaneously

a) 1/52 b) 2/51 c) 1/26 d)2/26
ii) If you draw a card from a deck, what is the probability that you will get the Ace of Diamonds and a black card?
a) 1/52 b) 2/51 c ) 1/26 d)2/26
iii)A fair coin is flipped five times and comes up heads each time. What is the probability that it will come up heads on the sixth flip?
a) 1 b) 1/3 c) 1/2 d)0
iv) If P(A) is the probability of Event A, then not A is denoted by
a) 1 - P(A) b) P(A) – 1 c) P(E) d) 1- P(E)
v) You throw 2 dice. What is the probability that the sum of the two dice will be 6?
a) 1/6 b)1/36 c) 5/36 d) 5/6

Answer 1

1/52 2/51 1/26 2/26 is very good answer