8.
Consider a two particle system with the particles having masses m, and m,. If the
first particle is pushed towards the centre of mass through a distance d, by what
distance should the second particle be moved, so as to keep the centre of mass at
the same position?
cm
Answers
Answer:
If x
1
and x
2
are the positions of masses m
1
and m
2
, the position of the centre of mass is given by x
cm
=
m
1
+m
2
m
1
x
1
+m
2
x
2
If x
1
changes by Δx
1
and x
2
changes by Δx
2
, the change in x
cm
will be
Δx
cm
=
m
1
+m
2
m
1
Δx
1
+m
2
Δx
2
.........(I)
Given Δx
cm
=0 and Δx
1
=d.
Using these values in eq.(i), we get m
1
d+m
2
Δx
2
=0
or Δx
2
=−
m
2
m
1
d
∴ Distance moved by m
2
=
m
2
m
1
d
, which is choice (a).
Explanation:
Answer:
ifc
x
2
x
abundens
so
multiply it by 2
composition
5*2
10
it is x
answer is 10
then
10=x
.
Explanation:
hope this may help u