Question

8.Construct a triangle similar to a given equilateral triangle PQR with side 5cm, such that each of its side is 5/7 of the corressponding sides of a triangle PQR



















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Answer 1

Step-by-step explanation:

Answer

Draw a line segment QR = 5 cm.

With Q as centre and radius = PQ = 5 cm, draw an arc.

Join PQ and PR to obtain ΔPQR.

Below QR, construct an acute ∠RQX.

Join Q7R.

Draw Q6R' || Q7R.

From R' draw R'P' || RP.

Hence, P'QR' is the required triangle.

Answer 2

Answer:

$\huge\blue{ANSWER:-}$

1.Draw a line segment QR = 5 cm.

2.With Q as centre and radius = PQ = 5 cm, draw an arc.

3.Join PQ and PR to obtain ΔPQR.

4.Below QR, construct an acute ∠RQX.

5.Join Q7R.

6.Draw Q6R' || Q7R.

7.From R' draw R'P' || RP.

8.Hence, P'QR' is the required triangle.