Question

8. Construct angle DEF such that DE = 5 cm, DF = 3 cm and m angle EDF = 90°​

Answer 1

Answer:

To construct: △DEF where DE=5cm,DF=3cm and m∠EDF=90

o

.

Steps of construction:

(a) Draw a line segment DF=3cm

(b) At point D an angle of 90

o

with the help of compass i.e., ∠XDF=90

o

.

(c) Taking D as centre, draw an arc of radius 5cm, which cuts DX at the point E

(d) Join EF

It is the required right angle triangle DEF

Step-by-step explanation:

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Answer 2

Answer:

To construct: △DEF where DE=5cm,DF=3cm and m∠EDF=90

o

.

Steps of construction:

(a) Draw a line segment DF=3cm

(b) At point D an angle of 90

o

with the help of compass i.e., ∠XDF=90

o

.

(c) Taking D as centre, draw an arc of radius 5cm, which cuts DX at the point E

(d) Join EF

It is the required right angle triangle DEF