Question

8. Construct right angles triangle PQR where m 2Q = 90°, QR = 8cm and PR = 10cm
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Answer 1

Answer:

• Draw a line segment QR=8cm.

• At point Q, draw QX ⊥ QR.

• With R as centre, draw an are of radius 10cm.

• This are cut the QX at point P.

• Join PR. Thus, right-angled ΔPQR is the required triangle.

$\huge \green{ \boxed{ done! }}$