Question

8 couples (husband and wife) attend a dance show "Nach Baliye' in a popular TV channel ; A lucky draw in which 4 persons picked up for a prize is held, then the probability that there is atleast one couple will be selected is :
A) 8/39
B) 15/39
C) 12/13
D) None of these

Answer 1

$\bf\huge\color{red}{SOLUTION;}$

P( selecting atleast one couple) = 1 - P(selecting none of the couples for the prize) 

 
 = 1 - {16^C^1*14^C^1*12^C^1*10^C^1/16^C^1}
= 15/39

Answer 2

Hey mate ^_^

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Answer:
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P (Selecting atleast one couple) = 1 - P (Selecting none of the couples for the prize) 

Now,

$= 1 - ( \frac{16c1\times 14c1 \times 12c1 \times 10c1}{16c4} )$

$= \frac{15}{39}$

Therefore,

Correct option B) $\frac{15}{39}$

#Be Brainly❤️