Math, asked by phanimaths, 1 year ago

8 couples (husband and wife) attend a dance show "Nach Baliye' in a popular TV channel ; A lucky draw in which 4 persons picked up for a prize is held, then the probability that there is atleast one couple will be selected is :0


kunalkumar2011: no there is 6 coupals

Answers

Answered by MarilynEvans
9
P(E) = No. of outcomes/total no. of outcomes

P(E) = 4/8

P(E) = 1/2

Thanks...!

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Answered by anamikasv
2

Answer:


Total People Attending: 16  

Ways To Choose 4 From 16: 16 x 15 x 14 x 13/4! = 1820  

Ways To Choose 4 Without Any Couples: 16 x 14 x 12 x 10/4! = 1120  

Ways To Choose 4 That Include One Or More Couple: 1820 - 1120 = 700  

Probability Of Choosing At Least One Couple: 700/1820 = 35/91 = 5/13

pls mark as brainliest


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