8 couples (husband and wife) attend a dance show "Nach Baliye' in a popular TV channel ; A lucky draw in which 4 persons picked up for a prize is held, then the probability that there is atleast one couple will be selected is :0
kunalkumar2011:
no there is 6 coupals
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P(E) = No. of outcomes/total no. of outcomes
P(E) = 4/8
P(E) = 1/2
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P(E) = 4/8
P(E) = 1/2
Thanks...!
Merry Christmas...!
With♥️
Answered by
2
Answer:
Total People Attending: 16
Ways To Choose 4 From 16: 16 x 15 x 14 x 13/4! = 1820
Ways To Choose 4 Without Any Couples: 16 x 14 x 12 x 10/4! = 1120
Ways To Choose 4 That Include One Or More Couple: 1820 - 1120 = 700
Probability Of Choosing At Least One Couple: 700/1820 = 35/91 = 5/13
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