Question

8(d-1)+17(d-3)=5(4d-4)+5​

Answer 1

8(d-1)+17(d-3)=(4d-4)+5

We move all terms to the left:

8(d-1)+17(d-3)-((4d-4)+5)=0

We multiply parentheses

8d+17d-((4d-4)+5)-8-51=0

We calculate terms in parentheses: -((4d-4)+5), so:

(4d-4)+5

We get rid of parentheses

4d-4+5

We add all the numbers together, and all the variables

4d+1

Back to the equation:

-(4d+1)

We add all the numbers together, and all the variables

25d-(4d+1)-59=0

We get rid of parentheses

25d-4d-1-59=0

We add all the numbers together, and all the variables

21d-60=0

We move all terms containing d to the left, all other terms to the right

21d=60

d=60/21

d=2+6/7

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Answer 2

Answer:

47/5

Step-by-step explanation:

8d-8+17d-54=20d-20+5

25d-62=20d-15

25d-20d=62-15

5d=47

d=47/5