Question

8. Derive the expression for distance travelled
By body in nth second of its motion

Answer 1

Answer:

Explanation:

let AB is distance traveled by body in n second and ac is distance travel by body in (n-1)second .

thus distance travel in nth second is CB

Sn=AB-AC

  from s=ut+1/2at2                                                     eq-3

AB=un+1/2an2                                                         eq-1

AC=u(n-1)+1/2a(n-1)2                                                  eq-2

from eq1,2,3

sn=un+1/2an2-(un-u+1/2an2-an+1/2a

sn=un+1/2an2-un+u-1/2an2+an-1/2a

sn=u+a(n-1/2)

sn=u + 1/2a(n-1/2)             or     sn=u+1/2a(2n-a)