Question

8-\dfrac {m}{n}+p^28− n
m
​ +p 2
8, minus, start fraction, m, divided by, n, end fraction, plus, p, squared when m=8m=8m, equals, 8, n=2n=2n, equals, 2, p=7p=7

Answer 1

Answer:

53

Step-by-step explanation:

Let's substitute 8- $\frac{m}{n}$ + p²

m= 8, n=2 and p=7

So, 8 - 4/2 + p²

8-4+49.

=53