Question

8. Diffusion current in Ilkovic equation is obtained in milliamperes when drop time is
expressed in seconds and
(a) Din cms)
, C in mole I', m in mg
(b) D in cm s 1, C in millimole 14., m in ga
(c) D in cm's, C in mole 1", min mg s
(d) D in cm’s ', C in milli mole l", m in mg s"​

Answer 1

Answer:

option a is correct answer

Explanation:

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Answer 2

Answer:

Option A

Explanation:

Ilkovic Equation  is written as

                              $I_{d}$  =   $708 n CD^{\frac{1}{2} } m^{\frac{2}{3} } t^{\frac{1}{6}}$

where,

$I_{d}$  = diffusion current, measured at the top of the oscillations in the Figure above with the units µA

n = number of electrons per molecule involved in the oxidation or reduction of the electroactive species.

C = concentration of electroactive species, with the units mol/L

D = diffusion coefficient of electroactive species, with the units $cm^{2} /s$

m =rate of flow of Hg, in $mg/s$

t = drop interval, in $s$

The number $708$ is a combination of several constants whose dimensions are such that  $I_{d}$  will be given in  µA

Hence, according to the above equation,  D is measured in cms, C in mole I', and m in mg.

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