Question

8. Draw the graph of the equation 2x-y +3=0. Using the graph, find the value of y, when x= -2 ​

Answer 1

$\large\underline{\sf{Solution-}}$

Given equation of line is

$\rm :\longmapsto\:2x - y + 3 = 0$

can be rewritten as

$\rm :\longmapsto\:y = 2x + 3$

Substituting 'x = 0' in the given equation, we get

$\rm :\longmapsto\:y = 2 \times 0 + 3$

$\rm :\longmapsto\:y = 0 + 3$

$\bf\implies \:y = 3$

Substituting 'x = 1' in the given equation, we get

$\rm :\longmapsto\:y = 2 \times 1 + 3$

$\rm :\longmapsto\:y = 2 + 3$

$\bf\implies \:y = 5$

Substituting 'x = 2' in the given equation, we get

$\rm :\longmapsto\:y = 2 \times 2 + 3$

$\rm :\longmapsto\:y = 4 + 3$

$\bf\implies \:y = 7$

Hᴇɴᴄᴇ,

➢ Pair of points of the given equation are shown in the below table.

$\begin{gathered}\boxed{\begin{array}{c|c} \bf x & \bf y \\ \frac{\qquad \qquad}{} & \frac{\qquad \qquad}{} \\ \sf 0 & \sf 3 \\ \\ \sf 1 & \sf 5 \\ \\ \sf 2 & \sf 7 \end{array}} \\ \end{gathered}$

➢ Now draw a graph using the points (0 , 3), (1 , 5) & (2 , 7)

➢ See the attachment graph.

So, from graph we concluded that

$\begin{gathered}\boxed{\begin{array}{c|c} \bf x & \bf y \\ \frac{\qquad \qquad}{} & \frac{\qquad \qquad}{} \\ \sf - 2 & \sf - 1 \end{array}} \\ \end{gathered}$