Question

8) Draw ZABC = 120° Draw its angle bisector.​

Answer 1

Step-by-step explanation:

Steps of Construction:

Steps of Construction:1.Construct a line segment BC.

Steps of Construction:1.Construct a line segment BC.2.Taking B as centre and some suitable radius construct an arc which meets BC at the point P.

Steps of Construction:1.Construct a line segment BC.2.Taking B as centre and some suitable radius construct an arc which meets BC at the point P.3. Taking P as centre and with same radius cut off the arcs PQ and QR.

Steps of Construction:1.Construct a line segment BC.2.Taking B as centre and some suitable radius construct an arc which meets BC at the point P.3. Taking P as centre and with same radius cut off the arcs PQ and QR.4.Now join BR and produce it to point A

Steps of Construction:1.Construct a line segment BC.2.Taking B as centre and some suitable radius construct an arc which meets BC at the point P.3. Taking P as centre and with same radius cut off the arcs PQ and QR.4.Now join BR and produce it to point A∠ABC=120

Steps of Construction:1.Construct a line segment BC.2.Taking B as centre and some suitable radius construct an arc which meets BC at the point P.3. Taking P as centre and with same radius cut off the arcs PQ and QR.4.Now join BR and produce it to point A∠ABC=120 o

Steps of Construction:1.Construct a line segment BC.2.Taking B as centre and some suitable radius construct an arc which meets BC at the point P.3. Taking P as centre and with same radius cut off the arcs PQ and QR.4.Now join BR and produce it to point A∠ABC=120 o

Steps of Construction:1.Construct a line segment BC.2.Taking B as centre and some suitable radius construct an arc which meets BC at the point P.3. Taking P as centre and with same radius cut off the arcs PQ and QR.4.Now join BR and produce it to point A∠ABC=120 o 5.Taking P and R as centres construct two arcs which intersect each other at the points S.

Steps of Construction:1.Construct a line segment BC.2.Taking B as centre and some suitable radius construct an arc which meets BC at the point P.3. Taking P as centre and with same radius cut off the arcs PQ and QR.4.Now join BR and produce it to point A∠ABC=120 o 5.Taking P and R as centres construct two arcs which intersect each other at the points S.6.Now join BS and produce it to point D.

Steps of Construction:1.Construct a line segment BC.2.Taking B as centre and some suitable radius construct an arc which meets BC at the point P.3. Taking P as centre and with same radius cut off the arcs PQ and QR.4.Now join BR and produce it to point A∠ABC=120 o 5.Taking P and R as centres construct two arcs which intersect each other at the points S.6.Now join BS and produce it to point D.Here BD is the bisector of ∠ABC

Steps of Construction:1.Construct a line segment BC.2.Taking B as centre and some suitable radius construct an arc which meets BC at the point P.3. Taking P as centre and with same radius cut off the arcs PQ and QR.4.Now join BR and produce it to point A∠ABC=120 o 5.Taking P and R as centres construct two arcs which intersect each other at the points S.6.Now join BS and produce it to point D.Here BD is the bisector of ∠ABCBy measuring each angle we get to know that is it 60

Steps of Construction:1.Construct a line segment BC.2.Taking B as centre and some suitable radius construct an arc which meets BC at the point P.3. Taking P as centre and with same radius cut off the arcs PQ and QR.4.Now join BR and produce it to point A∠ABC=120 o 5.Taking P and R as centres construct two arcs which intersect each other at the points S.6.Now join BS and produce it to point D.Here BD is the bisector of ∠ABCBy measuring each angle we get to know that is it 60 o

Steps of Construction:1.Construct a line segment BC.2.Taking B as centre and some suitable radius construct an arc which meets BC at the point P.3. Taking P as centre and with same radius cut off the arcs PQ and QR.4.Now join BR and produce it to point A∠ABC=120 o 5.Taking P and R as centres construct two arcs which intersect each other at the points S.6.Now join BS and produce it to point D.Here BD is the bisector of ∠ABCBy measuring each angle we get to know that is it 60 o yes,both the angles are of equal measure.