8. During a tennis match, a player hits the ball reaching a speed of 58 m/s. What is the average force exerted on the 0.057-kg tennis ball by the player, assuming that the ball’s speed just after impact is 58 m/s and that the initial horizontal component of the velocity before impact is negligible and that the ball remained in contact with the racquet for 5.0 ms (milliseconds)? IT IS URGENT PLEASE ANSWER
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The force which is exerted to the tennis ball is equal to661.2N
Explanation:
Given,
- The mass of the tennis ball is equal to 0.057 kg
- The change in the velocity that takes place is equal to 58 metre per second
- The impact of the time in which the change in in velocity takes place is 5/1000 sec
- Now , the acceleration is equal to the change in velocity per unit time
- A= dv/dt = 58x1000/5 m/ sec²
- The force is the product of acceleration and mass
- F= m• a = 0.057 x 58x 1000/5= 661.2N
To know more,
What is the kinematics - Brainly.in
https://brainly.in/question/5099338