Question

8. ਘਟਨਾ E ਦੀ ਸੰਭਾਵਨਾ + ਘਟਨਾ ‘E ਨਹੀਂ’ ਦੀ ਸੰਭਾਵਨਾ
ਹੁੰਦੀ ਹੈ।
a) 1
b) 0
c) 2
d) ਇੰਨਾਂ ਵਿੱਚੋਂ ਕੋਈ ਨਹੀਂ​

Answer 1

Given that,

Probability of event E + probability of event 'no'  occurs.

We know that,

Probability :

Probability is defined as the possibility.

Event occurs will be possible or not. This is probability of event.

We know the one rule of probability,

The sum of the probability of an event occurring or an event not occurring must be equal to one.

$P(E)+P'(E)=1$

Where, $P(E)$ = probability of occur event

$P'(E)$ = probability of not occur event

Hence, The probability of event E + probability of event 'no'  occurs equal to the 1.

(a) is correct option.

Answer 2

Given:

There is an event "E"

To Find:

Probability of event 'E' + Probability of event 'no E'  occurs

Solution:

We know,

An Event:-  According to the theory of probability, an event is a set of possible outcomes of an experiment.

Let's assume,

"P( E )" → probability of an event "E"  

"P( E' )" → probability of an event "no E"

So,

P(E) = $\frac{The \:no.\: of\: ways\: an\: event\: can\: happen}{The\:no. \:of\: possible\: outcomes}$

⇒ the probability of an event happening will always lie from 0 to 1

⇒ the sum of all the probabilities of all possible outcomes of an experiment is 1.

∴ P(E) = 1

and

P(E') is the complement of P(E)

∴ P(E') = 0

Now, we get

P(E) + P(E')

= 1 + 0

= 1 ← option (a)

Thus, the probability of event 'E' + probability of event 'no E'  occurs is 1.

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