Question

8. Evaluate : 9 sec2A-9tanA.

​

Answer 1

Step-by-step explanation:

We have, 9sec

2

A−9tan

2

A

Let r=9sec

2

A−9tan

2

A

r=9(sec

2

A−tan

2

A)

We know that

sec

2

A−tan

2

A=1

Therefore,

r=9×1=9

Hence, this is the answer.

Answer 2

He is right............