Question

8. Evaluate the following divisions:
(a) (3b – 6a) = (30a – 15b)
(b) (4x² – 100) = 6(x + 5)​

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

$(a). \: \: \: \frac{(3b - 6a)}{(30a - 15b)} = \frac{3(b -2 a)}{15(2a - b)} \\ = \frac{ - (2a - b)}{5(2a - b)} = - \frac{1}{5}$

$(b). \: \: \: \frac{(4 {x}^{2} - 100) }{6(x + 5)} = \frac{4( {x}^{2} - 25) }{6(x + 5)} \\ = \frac{2(x + 5)(x - 5)}{3(x + 5)} \\ = \frac{2(x - 5)}{3}$

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