Question

8.
Expand ( 4a-2b-3c)²?​

Answer 1

Answer:

Step-by-step explanation:

(4a-2b-3c)² = (4a + (-2b) + (-3c))²

Using (x+y+z)² = x² + y² + z² + 2xy + 2yz + 2zx

Let x = 4a, y = -2b, z = -3c

= (4a)² + (-2b)² + (-3c)² + 2 (4a)(-2b) + 2 (-2b)(-3c) + 2 (-3c)(4a)

= 16a² + 4b² + 9c² - 16ab + 12bc - 24ac