Question

8.
Explain the nature of the roots of.x2 - 4x + 3 = 0.
​

Answer 1

For roots D = b² - 4ac

D = (-4)² - 4(1)(3) = 0

16 - 12 = 0

4 > 0

so roots are real.

Answer 2

for root,

d=b^2-4ac

(-4)^2-4(1)(3)

16-12=4

since 4 is greater than 0

hence it is a real root