Question

8. Express (1 )(2 3 ) (5 )(3 )      i i i i in the form of x+iy

Answer 1

Answer:

5−3i)

3

=125+27i

3

+225i+135i

2

(5−3i)

3

=−10+198i

(ii)

1−

2

i

5+

2

i

=

1−

2

i

5+

2

i

×

1+

2

i

1+

2

i

=

1

2

−2i

2

5+5

2

i+

2

i+2i

2

=

1+2

5+6

2

i−2