8. Factorise each of the following:
1) 8a + b3 +12ab+ 6ab2
(iii) 27 -125a - 135a +225a2
1
9
1
273
2
(
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Answer:
1)(2a+b) (2a+b) (2a+b)
explanation is in attachment.
iii)125a3 + 27 + 135a + 225a2
= 125a3 + 225a2 + 135a + 27
= (5a)3 + 3 × (5a)2 × (3) + 3 × (5a) × (3)2 + 33
= (5a + 3)3 [Since, a3 + 3a2b + 3ab2 + b3
= (a + b)3] (b) 3m - 24m4
= 3m(1− 8m3)
= 3m[13− (2m)3]
= 3m [1 − 2m] [12 + 2m + (2m)2] [Since, (a3 − b3)
= (a − b)(a2 + ab + b2 ]
= 3m [1 − 2m] [1 + 2m + 4m2]
Attachments:
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