Math, asked by jaishree44044, 6 months ago

8. Factorise each of the following:
(1) 8a3+ b3 + 12ab + 6ab2
(iii) 27 -125a - 135a +225a²
(ii) 8a-b3 -12a2b +6ab2
(iv) 64a3-27b3-144a²b + 108ab2
(v)27p3-1/216-9/2p2+1/4p​

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Answers

Answered by pukultanvi4444
0

Answer:

(i)8a3+6ab2+b3+12ab-Cannot factor

(ii)Factor 27−125a−135a+225a2

=225a2−260a+27

Doesn't factor

(iii)8a−b3−12a2b+6ab2

Cannot factor

(iv)64a3−27b3−144a2b+108ab2

Cannot factor

(v) Let's simplify step-by-step.

27p3−

1

216

9

2

p2+

1

4

p

=27p3+

−1

216

+

−9

2

p2+

1

4

p

Answer:

=27p3+

−9

2

p2+

1

4

p+

−1

216

Answered by mdjabedfeni23
0

Step-by-step explanation:

12a²-8a-32, 4a-8,3a+4

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