Math, asked by Anonymous, 8 months ago

8. Factorise each of the following:
(i) 8a + b3 + 12a²b + 6ab2​

Answers

Answered by Siddharta7
5

Answer:

(2a - b)(2a - b)(2a - b)

Step-by-step explanation:

8a³- b³- 12a²b + 6ab²

=(2a - b)(4a² + 2ab + b²) - 6ab(2a - b)

=(2a - b)(4a² + 2ab + b² - 6ab)

=(2a - b)(4a² - 4ab + b²)

=(2a - b){(2a)² - 2 × 2a × b + (b)²}

=(2a - b)(2a - b)²

=(2a - b)(2a - b)(2a - b)

Hope it helps!

Answered by Anonymous
5

Answer:

(2a - b)(2a - b)(2a - b)

Step-by-step explanation:

8a³- b³- 12a²b + 6ab²

=(2a - b)(4a² + 2ab + b²) - 6ab(2a - b)

=(2a - b)(4a² + 2ab + b² - 6ab)

=(2a - b)(4a² - 4ab + b²)

=(2a - b){(2a)² - 2 × 2a × b + (b)²}

=(2a - b)(2a - b)²

=(2a - b)(2a - b)(2a - b)

HopeDearHelps!!.......

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