8. Factorise each of the following:
(i) 8a + b3 + 12a²b + 6ab2
Answers
Answered by
5
Answer:
(2a - b)(2a - b)(2a - b)
Step-by-step explanation:
8a³- b³- 12a²b + 6ab²
=(2a - b)(4a² + 2ab + b²) - 6ab(2a - b)
=(2a - b)(4a² + 2ab + b² - 6ab)
=(2a - b)(4a² - 4ab + b²)
=(2a - b){(2a)² - 2 × 2a × b + (b)²}
=(2a - b)(2a - b)²
=(2a - b)(2a - b)(2a - b)
Hope it helps!
Answered by
5
Answer:
(2a - b)(2a - b)(2a - b)
Step-by-step explanation:
8a³- b³- 12a²b + 6ab²
=(2a - b)(4a² + 2ab + b²) - 6ab(2a - b)
=(2a - b)(4a² + 2ab + b² - 6ab)
=(2a - b)(4a² - 4ab + b²)
=(2a - b){(2a)² - 2 × 2a × b + (b)²}
=(2a - b)(2a - b)²
=(2a - b)(2a - b)(2a - b)
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