8. Fig. 14.145, ABC is a triangle inscribed in a circle,
AB = AC = 10 cm, BC = 16 cm. The chord AE is at
right angles to the chord BC at D. Calculate DE and
the radius of the circle.
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Given: Right △ABC with two sides 6 cm and 8 cm. ∠A=90
∘
To find the incircle of the triangle.
In △ABC
AB
2
+AC
2
=BC
2
6
2
+8
2
=BC
2
BC=10 cm
Incircle=
Sumofsides
2×Area
Incircle=
AB+AC+BC
2×(
2
1
AB×AC)
Incircle=
6+8+10
6×8
Incircle=
24
48
incircle=2 cm
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