Question

8. Find a Pythagorean triplet whose greatest
member is 17​

Answer 1

So, the Pythagoras triplet whose one number is 17 is =8,15,17.

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Answer 2

Answer:

Here is the answer:

Step-by-step explanation:

Pythagoral triplets =2m, m^2-1,m^2+1.

Where m^2+1 is the greatest =17

m^2+1=17

m^2=17-1

=16

m=√16

m=4

Thus 2m=8,m^2-1=15

So the Pythagoral triplets are 8,15 and 17.

VERIFICATION:-

(m^2+1)^2=2m^2+(m^2-1)^2

17^2=8^2+15^2

289=64+225

289=289

Thus LHS=RHS

Hence 8,15,17 are verified Pythagoral triplets.

HOPE IT HELPS.

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