Math, asked by duraisami658, 10 months ago

8. Find a Pythagorean triplet whose
(i) largest member is 65 ​

Answers

Answered by hanumant73
1

Answer:

(65)^=65*65=4225

4225=a^+b^

25,64and 65

Answered by nirdesh86
1

Answer:

2m m^2+1 m^2-1

2m=65 (33.5)^2+1 (33.5)^2-1

m=65/2 67+1 67-1

m=32.5 68 66

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