Question

8.Find an A.P.of 8terms whose first term is (1)/(2) and last term is (17)/(6) .

Answer 1

Answer:

Step-by-step explanation:

given

1st term = 1/2

last term = 17/6

number of terms =8

nth term = 1st term + (n-1) d

   17/6  = 1/2 + ( 8- 1) d

  17/6 -1/2 = 7 d

  17 - 3 /6 = 7 d

  14/ 6 = 7 d

   2/6 =d

d = 1/3

AP is,

1/2 , 5/6, 7/6 , 9/6 , 11/6 ,13/ 6, 15/6 , 17/6

hope it helps

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