Question

8. Find out by division whether the smaller number is a factor of the larger number.
a) 18, 72
b) 28, 114
c) 15,135​

Answer 1

Answer:

The smallest number which when divided by 18,27, and 36 leaves a remainder 5 in each case is 113.

Step-by-step explanation:

Given:

Find the smallest number which when divided by 18,27, and 36 leaves a remainder 5 in each case.

Solution:

To find the common number that divides all the given 3 numbers,

LCM of 18, 27, 36 = 2 \times 2 \times 3 \times 3 \times 32×2×3×3×3 = 108

Smallest number that leaves a remainder 5 = 108 + 5 = 113

Result:

The smallest number which when divided by 18,27, and 36 leaves a remainder 5 in each case is 113.