Question

(8) Find out ratio of moles of oxygen atoms in 44.8L of CO2 at STP to 16 gms of ozone (O3) ​

Answer 1

Answer:

6:1

Explanation:

so using pv=nrt

at stp p=1atm

t= 273k

44.8×1=0.0821×273×n

44.8=22.4n

n=2 mol

c+o2=>co2

2c+2o2=>2co2

there is 2mol o2 in 2mol co2

no of moles of o3 is 16/48=1/3

ratio =2:1/3

6:1

Answer 2

Answer:

6.1 is the answer please give me a thanks and mark me as a brainliest