Question

8. FIND RATIO BY MASS OF FOLLWING: NH3, SO2, CHOH, C6H1206, NH,OH, MgO, CHA​

Answer 1

Answer:

~In So2

, molar mass of S = 32 g mole

−1

& molar mass of O

2

= 32 g mol

−1

Therefore the ratio of their masses = 32:32 = 1:1

~In nh3The ratio by mass of Nitrogen with Hydrogen in ammonia is 14:3

~The ratio should be close to 1:1 as the formula of magnesium oxide is mgo. Example calculation: Mass magnesium = 2.39 g. Mass magnesium oxide = 3.78 g.

sry I don't know other's