Question

8. Find the area of the shaded portion.
(a)
14m
6m
I I
8m
4m
10m
T
6m
2m
4m
16
20m
3.​

Answer 1

Answer:

80 sq m

Step-by-step explanation:

Area of rectanguler figure = L x B

10 x 20 = 200 sq m

Area of tringle i

1/2 base x hight = 1/2 x 8 x 14 = 56 sq m

area 2 triangle = 1/2 x base x hight

1/2 x 6 x 4 = 12 sq m

Area of third triangle= 1/2 x base x hight

1/2 x 6 x 16 =48 sq m

Area of forth triangle = 1/2 x base x hight

1/2 x 2 x 4 = 4 sq m

Area of unshaded region = 56 + 12+48+4 = 120 sq m

Now area of shaded region = total area of fingure - unshaded region

200 - 120 = 80 sq m

Answer 2

Step-by-step explanation:

area of the rectangle including the inner quadrilateral=20*10=200m²

area of the in a quadrilateral is equal to area of the triangles on each corner subtracted from area of the rectangle which is 200 metre square

area of triangle number 1 is equal to ½×4*2 =4

area of the rectangle number 2 is equal to ½ x 8 x 14= 56

area of the rectangle number three is equal to ½*6*4=12

area of the rectangle number 4 is equal to ½*6*16=48

4+56+12+48=120 m²

200m²-120m²=60m²