Question

8. Find the area of triangle ABC whose vertices are A (-5, 7), B (-4, -5) and C (4, 5).

Answer 1

Answer:

53 sq. units

Step-by-step explanation:

$A (-5, 7), B (-4, -5) \: and \: C (4, 5). \\ area = \frac{1}{2} | - 5( - 5 - 5) + ( - 4)(5 - 7) + 4(7 - ( - 5))| \\ \\ = > \frac{1}{2} |50 + 8 + 48| \\ \\ = > \frac{1}{2} \times 106 \\ \\ = > 53 \: sq.units$

Answer 2

Answer:

Hopefully that's helpful for you....