Question

8. Find the diagonal of a rectangle whose length is 35 cm and breadth is 12 cm.​

Answer 1

$\underline { \blue { Dimensions \:of \: a \: rectangle : }}$

$Length (l) = 35 \:cm , \: Breadth (b) = 12 \:cm$

$\pink { Diagonal \:of \:the \: rectangle } \\= \blue { \sqrt{ l^{2} + b^{2}}} \\= \sqrt{35^{2} + 12^{2}} \\= \sqrt{1225 + 144 } \\= \sqrt{1369}\\= \sqrt{37^{2}}\\= 37 \:cm$

Therefore.,

$\red{ Diagonal \:of \:the \: rectangle }\green {=37 \:cm}$

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Answer 2

Answer:

Diagonal of rectangle is 37 cm.

Step-by-step-explanation:

The diagonal of rectangle is like a hypotenuse.

So, by Pythagors Theorem

(Hypotenuse)² = (Length)² + (Breadth)²

=> (Diagonal)² = (35)² + (12)²

=> (Diagonal)² = 1225 + 144

=> (Diagonal)² = 1369

=> Diagonal = 37 cm

Hence,

Diagonal of rectangle is 37 cm.