Math, asked by bhavana425676, 2 months ago

8. Find the distance of the point(3,-5) from the line 3x-4 y-26 = 0​

Answers

Answered by neeleshpravin
1

Answer:

Step-by-step explanation:

The shortest distance between the point (3,-5) and the like 3x-4y-26=0 will be the line perpendicular to given line.

length of perpendicular = ax'+by'+c/ |a^2+b^2|

Here ;

a =3

b= -4

c= -26

x' = 3

y'= -5

Length = |(3×3) + (-4×-5) + (-26)}|/ √(3^2+(-4)^2)

= |9 +29 -26| / √9+16

= 12/5

therefore the distance will be 12/5 units.

hope it helped.. ...!☺

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