8) Find the equation of the parabola whose focus is (-3, 0) and the equation of the directrix is x = 3.
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Answer:
According to definition of parabola , is is the locks of the points in that planes that are equidistant from both focus and directrix.
Given, focus : (-3,0)
directrix : x + 5 = 0
Let (x ,y) is the point on the parabola .
∴ distance of point from focus = distance of point from directrix
⇒
(x+3)
2
+y
2
=∣x+5∣/
(1
2
+0
2
)
⇒
(x+3)
2
+y
2
=∣x+5∣
squaring both sides,
(x + 3)² + y² = (x + 5)²
⇒y² = (x + 5)² - (x + 3)²
⇒y² = (x + 5 - x - 3)(x + 5 + x + 3)
⇒y² = 2(2x + 8) = 4(x + 4)
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