Question

8. Find the equation of the straight line parallel to the line 3x-y+y=0 and passing
through the point (1, -2).

Answer 1

3x-y+y =2
-y+y=2+3=0
y=0
1,-2 fourth quadrant

Answer 2

Solution :

Equation of the line parallel to

3x - y + k = 0 is

3x - y + p = 0 it is passing through

( 1 , -2 ) ,

then

3( 1 ) - ( -2 ) + p = 0

=> 3 + 2 + p = 0

=> p = -5

Therefore ,

Required equation is

3x - y - 5 = 0

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