8 Find the force of attraction between a point charge of +4 C and a point charge of -5 C when they are situated in air at a distance of 30 cm from each other.
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Answer:
Two point charges of +1μC and +4μC are kept 30cm apart. How far from the +1μC charge on the line joining the two charge, will the net electric field be zero ?
Explanation:
Given ,
Two charge q
1
=+1μC
q
p
=1μC
q
2
=4μC
d=30cm=.3m
Let point P (where, f
1μC
=0) is at distance r from q
1
[ref. image]
F
1
+F
2
=0
k
r
2
q
1
×q
p
−k
(.3−r)
2
q
1
q
p
=0
r
2
q
1
=
(∗.−2)
2
q
2
(
r
.3−r
)
2
=
q
1
q
2
=
1
4
=4
(
r
.3−r
)
2
=4 or
r
.3−r
=2
r
.3−r
=+2
r=.1m=10cm
solution
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