Physics, asked by chetankhachane655, 5 hours ago

8 Find the force of attraction between a point charge of +4 C and a point charge of -5 C when they are situated in air at a distance of 30 cm from each other.​

Answers

Answered by isaacchrislobo
1

Answer:

Two point charges of +1μC and +4μC are kept 30cm apart. How far from the +1μC charge on the line joining the two charge, will the net electric field be zero ?

Explanation:

Given ,

Two charge q  

1

=+1μC

q  

p

=1μC

q  

2

=4μC

d=30cm=.3m

Let point P (where, f  

1μC

=0) is at distance r from q  

1

   [ref. image]

F  

1

+F  

2

=0

k  

r  

2

 

q  

1

×q  

p

 

−k  

(.3−r)  

2

 

q  

1

q  

p

 

=0

r  

2

 

q  

1

 

=  

(∗.−2)  

2

 

q  

2

 

 

(  

r

.3−r

)  

2

=  

q  

1

 

q  

2

 

=  

1

4

=4

(  

r

.3−r

)  

2

=4  or    

r

.3−r

=2

r

.3−r

=+2

r=.1m=10cm

solution

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