Question

8. Find the greatest number of children to whom 120 mangoes, 320 cavas and 180 bananas can be a equally distributed. Find also the share of each.
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Answer 1

Answer:

Step-by-step explanation:

No. of mangoes- 120

No. of Cavas- 320

Greatest no. of children to whom it can be distributed= HCF of 120 and 320

(HCF= HIGHEST COMMON FACTOR)

HCF= 40

Hence, the highest no. of children to whom 120 mangoes and 320 cavas can be equally distributed is 40.

Answer 2

Answer:

HCF OF 120,320 & 180 IS 20

therefore greatest number of children 20

share of each. mangoes:Cavas:Bananas = 6:16:9