Question

8. Find the HCF using prime factorisation method.
c) 28, 84, 49
d) 225, 150, 180
a) 11, 13, 10
b) 36,54,45
with explanation ​

Answer 1

ANSWER

a) 1

b)9

c)7

d)15

Step-by-step explanation:

a)

11 = 1 x 11

13=1x13

10=1x2x5

HCF=1

b)

36=2x2x3x3

54=2x3x3x3

45=5x3x3

HCF=3X3=9

c)

28=7x2x2

84=2x2x3x7

49=7x7

HCF =7

d)

225=3x5x3x5

150= 3x5x2x5

180= 3x5x2x2x3

HCF=3x5=15